JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    The energy liberated on complete fission of 1 kg of \[_{92}{{U}^{235}}\] is (Assume 200 MeV energy is liberated on fission of 1 nucleus)                                                                 [UPSEAT 2003]

    A)            \[8.2\times {{10}^{10}}J\]      

    B)            \[8.2\times {{10}^{9}}J\]

    C)            \[8.2\times {{10}^{13}}J\]      

    D)            \[8.2\times {{10}^{16}}J\]

    Correct Answer: C

    Solution :

                       Mass of a uranium nucleus                    \[=92\times 1.6725\times {{10}^{-27}}+143\times 1.6747\times {{10}^{-27}}\]                    \[=393.35\times {{10}^{-27}}kg\]                    Number of nuclei in the given mass                    \[=\frac{1}{393.35\times {{10}^{-27}}}=2.542\times {{10}^{24}}\]                    Energy released \[=200\times 2.542\times {{10}^{24}}MeV\]                    \[=5.08\times {{10}^{26}}MeV=8.135\times {{10}^{13}}J=8.2\times {{10}^{13}}J\]


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