JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    If an electron and a positron annihiliate, then the energy released is                                       [DCE 2001; AIIMS 2004]

    A)            \[3.2\times {{10}^{-13}}J\]     

    B)            \[1.6\times {{10}^{-13}}J\]

    C)            \[4.8\times {{10}^{-13}}J\]     

    D)            \[6.4\times {{10}^{-13}}J\]

    Correct Answer: B

    Solution :

                       Mass of electron = mass of positron = 9.1 ´ 10-31kg Energy released \[E=(2m).{{c}^{2}}\] \[=2\times 9.1\times {{10}^{-31}}\times {{(3\times {{10}^{8}})}^{2}}\]= 1.6 ´ 10?13J.


You need to login to perform this action.
You will be redirected in 3 sec spinner