A) \[6\times {{10}^{18}}\]
B) \[6\times {{10}^{17}}\]
C) \[{{10}^{17}}\]
D) \[6\times {{10}^{16}}\]
Correct Answer: A
Solution :
Number of fissions per second \[=\frac{Power\ output}{Energy\ released\ per\ fission}\] \[=\frac{3.2\times {{10}^{6}}}{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}=1\times {{10}^{17}}\] \[\Rightarrow \]Number of fission per minute \[=60\times {{10}^{17}}=6\times {{10}^{18}}\]
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