A) \[8\times {{10}^{13}}\,J\]
B) \[6\times {{10}^{27}}\,J\]
C) \[2\times {{10}^{7}}\,KwH\]
D) \[8\times {{10}^{23}}\,MeV\]
Correct Answer: D
Solution :
Fusion reaction of deuterium is \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\to }_{2}}H{{e}^{3}}{{+}_{0}}{{n}^{1}}+3.27\ MeV\] So \[E=\frac{6.02\times {{10}^{23}}\times {{10}^{3}}\times 3.27\times 1.6\times {{10}^{-13}}}{2\times 2}\]\[=7.8\times {{10}^{13}}J\] \[=8\times {{10}^{13}}J\].
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