JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    If a proton and anti-proton come close to each other and annihilate, how much energy will be released [DCE 1999; 2003]

    A)            \[1.5\times {{10}^{-10}}J\]     

    B)            \[3\times {{10}^{-10}}J\]

    C)            \[4.5\times {{10}^{-10}}J\]     

    D)            None of these

    Correct Answer: B

    Solution :

                       Mass of proton = mass of antiproton                    \[=1.67\times {{10}^{-27}}kg=1amu\]                    Energy equivalent to \[1\ amu=931\ MeV\]                    So energy equivalent to 2 amu \[=2\times 931\ MeV\]                    \[=1862\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\]\[=2.97\times {{10}^{-10}}J\]   \[=3\times {{10}^{-10}}J\].


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