JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    The masses of neutron and proton are 1.0087 a.m.u. and 1.0073  a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931MeV) [CPMT 1986; MP PMT 1995; CBSE PMT 2003]

    A)            28.4 MeV                               

    B)            20.8 MeV

    C)            27.3 MeV                               

    D)            14.2 MeV

    Correct Answer: A

    Solution :

               B.E.= Dmc2\[=[2(1.0087+1.0073)-4.0015]=28.4\ MeV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner