JEE Main & Advanced Mathematics Sequence & Series Question Bank nth term of special series, Sum to n terms and Infinite number of terms

  • question_answer
    The sum of \[{{1}^{3}}+{{2}^{3}}+{{3}^{3}}+{{4}^{3}}+.....+{{15}^{3}}\],is  [MP PET 2003]

    A) 22000

    B) 10,000

    C) 14,400

    D) 15,000

    Correct Answer: C

    Solution :

    Sum of cubes of \['n'\] natural number \[=\frac{{{n}^{2}}{{(n+1)}^{2}}}{4}=\frac{{{15}^{2}}{{(16)}^{2}}}{4}=14,400\].


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