A) 1 : 1
B) 1 : 4
C) 1 : 8
D) 1 : 16
Correct Answer: D
Solution :
\[S\propto {{u}^{2}}\Rightarrow \frac{{{S}_{1}}}{{{S}_{2}}}={{\left( \frac{1}{4} \right)}^{2}}=\frac{1}{16}\]
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