A) 15 m/sec
B) 25 m/sec
C) 5 m/sec
D) None of these
Correct Answer: A
Solution :
\[\because a=\frac{dv}{dt}=2(t-1)\]\[\Rightarrow dv=2(t-1)\ dt\] \[\Rightarrow \nu =\int_{0}^{5}{2}\ (t-1)dt=2\left[ \frac{{{t}^{2}}}{2}-t \right]_{0}^{5}\]\[=2\left[ \frac{25}{2}-5 \right]\] = 15 m/s
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