A) \[a\propto {{t}^{2}}\]
B) \[a\propto 2t\]
C) \[a\propto {{t}^{3}}\]
D) \[a\propto t\]
Correct Answer: D
Solution :
\[x\propto {{t}^{3}}\] \[\therefore \]\[x=K{{t}^{3}}\] \[\Rightarrow v=\frac{dx}{dt}=3\ K{{t}^{2}}\]and \[\Rightarrow a=\frac{dv}{dt}=6\ Kt\] i.e. \[a\propto t\]
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