A) \[-5\,m/s\]
B) \[6\,m/s\]
C) \[-3\,m/s\]
D) \[3\,m/s\]
Correct Answer: A
Solution :
The velocity of the particle is \[\frac{dx}{dt}=\frac{d}{dt}(2-5t+6{{t}^{2}})=(0-5+12t)\] For initial velocity \[t=0\], hence \[v=-5\ m/s\].
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