A) 5 ms?1
B) 8 ms?1
C) 10 ms?1
D) 12 ms?1
Correct Answer: C
Solution :
Let student will catch the bus after t sec. So it will cover distance ut. Similarly distance travelled by the bus will be \[\frac{1}{2}a{{t}^{2}}\] for the given condition \[ut=50+\frac{1}{2}a{{t}^{2}}=50+\frac{{{t}^{2}}}{2}\] [\[a=1\ m/{{s}^{2}}\]] Þ u \[=\frac{50}{t}+\frac{t}{2}\] To find the minimum value of u \[\frac{du}{dt}=0\], so we get \[t=10\sec \], then \[u=10\ m/s\]
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