A) 750 m
B) 800 m
C) 700 m
D) 850 m
Correct Answer: A
Solution :
Velocity acquired by body in 10sec \[v=0+2\times 10=20m/s\] and distance travelled by it in 10 sec \[{{S}_{1}}=\frac{1}{2}\times 2\times {{(10)}^{2}}=100\ m\] then it moves with constant velocity (20m/s) for \[30\ \sec \] \[\ {{S}_{2}}=20\times 30=600\ m\] After that due to retardation \[(4m/{{s}^{2}})\]it stops \[{{S}_{3}}=\frac{{{v}^{2}}}{2a}=\frac{{{(20)}^{2}}}{2\times 4}=50m\] Total distance travelled \[{{S}_{1}}+{{S}_{2}}+{{S}_{3}}=750m\]
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