JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    Equation of displacement for any particle is \[s=3{{t}^{3}}+7{{t}^{2}}+14t+8m\]. Its acceleration at time \[t=1\] sec is [CBSE PMT 2000]

    A)             10 m/s2           

    B)             16 m/s2

    C)             25 m/s2           

    D)             32 m/s2

    Correct Answer: D

    Solution :

                    \[s=3{{t}^{3}}+7{{t}^{2}}+14t+8\ m\]             \[a=\frac{{{d}^{2}}s}{d{{t}^{2}}}=18t+14\] at \[t=1\ \sec \Rightarrow a=32m/{{s}^{2}}\]


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