A) 0.01 ms?2
B) 0.02 ms?2
C) 0.03 ms?2
D) 0.04 ms?2
Correct Answer: B
Solution :
\[\text{Time}=\frac{\text{Distance}}{\text{Average velocity}}=\frac{3.06}{0.34}=9\ \sec \] Acceleration\[=\frac{\text{Change in velocity }}{\text{Time }}\]\[=\frac{0.18}{9}\]=0.02\[m/{{s}^{2}}\]
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