JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 m, the magnitude of the force is                           [EAMCET (Engg.) 2000]

    A)             \[3N\]  

    B)             \[3.5N\]

    C)             \[4.0N\]           

    D)             \[4.5N\]

    Correct Answer: D

    Solution :

                    \[u=0,S=250m,\ t=10\sec \ \]             \[S=ut+\frac{1}{2}a{{t}^{2}}\]Þ\[250=\frac{1}{2}a{{[10]}^{2}}\Rightarrow a=5m/{{s}^{2}}\]             So, \[F=ma=0.9\times 5=4.5N\]


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