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JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    The relation \[3t=\sqrt{3x}+6\] describes the displacement of a particle in one direction where \[x\] is in metres and \[t\] in sec. The displacement, when velocity is zero, is     [CPMT 2000]

    A)             24 metres        

    B)             12 metres

    C)             5 metres          

    D)             Zero

    Correct Answer: D

    Solution :

                    \[3t=\sqrt{3x}+6\Rightarrow 3x={{(3t-6)}^{2}}\]             \[\Rightarrow x=3{{t}^{2}}-12t+12\]             \[v=\frac{dx}{dt}=6t-12\], for \[v=0,\ t=2\sec \]             \[x=3{{(2)}^{2}}-12\times 2+12=0\]


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