A) Uniform acceleration
B) Uniform velocity
C) Increasing acceleration
D) Decreasing velocity
Correct Answer: A
Solution :
\[s\propto {{t}^{2}}\] (given)\[\therefore \] \[s=K{{t}^{2}}\] Acceleration \[a=\frac{{{d}^{s}}s}{d{{t}^{2}}}=2k\] (constant) It means the particle travels with uniform acceleration.
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