2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Motion in a Straight Line / सरल रेखा में गति

JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    The motion of a particle is described by the equation \[x=a+b{{t}^{2}}\] where \[a=15\] cm and \[b=3\] cm/s2. Its instantaneous velocity at time 3 sec will be [AMU (Med.) 2000]

    A)             36 cm/sec       

    B)             18 cm/sec

    C)             16 cm/sec       

    D)             32 cm/sec

    Correct Answer: B

    Solution :

                    \[x=a+b{{t}^{2}},\ v=\frac{dx}{dt}=2bt\]             Instantaneous velocity \[v=2\times 3\times 3=18\ cm/\sec \]


You need to login to perform this action.
You will be redirected in 3 sec spinner