A) Increasing with time
B) Decreasing with time
C) Constant but not zero
D) Zero
Correct Answer: A
Solution :
\[S=k{{t}^{3}}\] \[\therefore \] \[a=\frac{{{d}^{2}}S}{d{{t}^{2}}}=6kt\] i.e. \[a\propto t\]
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