A) 10 sec
B) 20 sec
C) 30 sec
D) 35 sec
Correct Answer: B
Solution :
Let A and B will meet after time t sec. it means the distance travelled by both will be equal. \[{{S}_{A}}=ut=40t\] and \[{{S}_{B}}=\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\times 4\times {{t}^{2}}\] \[{{S}_{A}}={{S}_{B}}\Rightarrow 40t=\frac{1}{2}4{{t}^{2}}\Rightarrow t=20\]sec
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