A) 20 \[m{{s}^{-2}}\]
B) 10\[m{{s}^{-2}}\]
C) 2 \[m{{s}^{-2}}\]
D) 1 \[m{{s}^{-2}}\]
Correct Answer: D
Solution :
\[u=72\ kmph=20m/s,\] \[v=0\] By using \[{{v}^{2}}={{u}^{2}}-2as\]Þ \[a=\frac{{{u}^{2}}}{2s}\]\[=\frac{{{(20)}^{2}}}{2\times 200}=1\ m/{{s}^{2}}\]
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