JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
     If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s. Then it covers a distance of   [CBSE PMT 1997]

    A)             20 m   

    B)             400 m

    C)             1440 m

    D)             2880 m

    Correct Answer: B

    Solution :

                    Here\[v=144\ km/h=40m/s\] \[v=u+at\]Þ \[40=0+20\times a\Rightarrow a=2\ m/{{s}^{2}}\]             \[\therefore \] \[s=\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\times 2\times {{(20)}^{2}}=400\ m\]


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