A) 0.20 \[m/{{s}^{2}}\]
B) 0.027 \[m/{{s}^{2}}\]
C) 0.218 \[m/{{s}^{2}}\]
D) 0.03 \[m/{{s}^{2}}\]
Correct Answer: C
Solution :
\[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] Þ \[1.2=0+\frac{a}{2}(2\times 6-1)\] Þ \[a=\frac{1.2\times 2}{11}=0.218\ m/{{s}^{2}}\]
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