A) Zero
B) \[8\,\,m/{{s}^{2}}\]
C) 20 \[m/{{s}^{2}}\]
D) 40 \[m/{{s}^{2}}\]
Correct Answer: B
Solution :
\[a=\sqrt{a_{x}^{2}+a_{y}^{2}}\] \[={{\left[ {{\left( \frac{{{d}^{2}}x}{d{{t}^{2}}} \right)}^{2}}+{{\left( \frac{{{d}^{2}}y}{d{{t}^{2}}} \right)}^{2}} \right]}^{\frac{1}{2}}}\] Here\[\frac{{{d}^{2}}y}{d{{t}^{2}}}=0\]. Hence \[a=\frac{{{d}^{2}}x}{d{{t}^{2}}}=8m/{{s}^{2}}\]
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