A) \[3m{{s}^{-1}}\]
B) \[-12m{{s}^{-1}}\]
C) \[42\,m{{s}^{-1}}\]
D) \[-9\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
\[v=\frac{ds}{dt}=3{{t}^{2}}-12t+3\] and \[a=\frac{dv}{dt}=6t-12\] For \[a=0\], we have \[t=2\] and at \[t=2,\ v=-9\ m{{s}^{-1}}\]
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