JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    The displacement is given by \[x=2{{t}^{2}}+t+5\], the acceleration at  \[t=2s\] is                                  [EAMCET (Engg.) 1995]

    A)             \[4\,\,m/{{s}^{2}}\] 

    B)             \[8\,\,m/{{s}^{2}}\]

    C)             \[10\,m/{{s}^{2}}\] 

    D)             \[15\,m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

                    Displacement \[x=2{{t}^{2}}+t+5\]             Velocity \[=\frac{dx}{dt}=4t+1\]             Acceleration \[=\frac{{{d}^{2}}x}{d{{t}^{2}}}=4\] i.e. independent of time             Hence acceleration \[=4\ m/{{s}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner