A) \[3\,m/{{\sec }^{2}}\]
B) \[-3m/{{\sec }^{2}}\]
C) \[0.3\,m/{{\sec }^{2}}\]
D) \[-0.3\,m/{{\sec }^{2}}\]
Correct Answer: B
Solution :
\[v=u+at\Rightarrow -2=10+a\times 4\Rightarrow a=-3m/se{{c}^{2}}\]
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