JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    The displacement \[x\]  of a particle along a straight line at time \[t\] is given by \[x={{a}_{0}}+{{a}_{1}}t+{{a}_{2}}{{t}^{2}}\]. The acceleration of the particle is              [NCERT 1974; RPMT 1999; AFMC 1999]

    A)             \[{{a}_{0}}\] 

    B)             \[{{a}_{1}}\]

    C)             \[2{{a}_{2}}\]           

    D)             \[{{a}_{2}}\]

    Correct Answer: C

    Solution :

                    Acceleration \[=\frac{{{d}^{2}}x}{d{{t}^{2}}}=2{{a}_{2}}\]


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