JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Non-uniform Motion

  • question_answer
    The initial velocity of the particle is \[10\,\,m/\sec \] and its retardation is \[=8\times \frac{9}{2}=36\ m\]. The distance moved by the particle in \[5th\]  second of its motion is                     [CPMT 1976]

    A)             \[1\,\,m\]          

    B)             \[19\,\,m\]

    C)             \[50\,\,m\]        

    D)             \[75\,m\]

    Correct Answer: A

    Solution :

                    \[{{S}_{n}}=u-\frac{a}{2}(2n-1)\]\[=10-\frac{2}{2}(2\times 5-1)=1\ meter\]


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