A) \[v=u+a{{t}^{2}}\]
B) \[v=u+a\frac{{{t}^{2}}}{2}\]
C) \[v=u+at\]
D) \[v=u\]
Correct Answer: B
Solution :
If acceleration is variable (depends on time) then \[v=u+\int{(f)}\ dt\]\[=u+\int{(a\ t)}\ dt\]\[=u+\frac{a\ {{t}^{2}}}{2}\]
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