A) \[{{S}_{1}}={{S}_{2}}\]
B) \[{{S}_{1}}={{S}_{2}}/3\]
C) \[{{S}_{1}}={{S}_{2}}/2\]
D) \[{{S}_{1}}={{S}_{2}}/4\]
Correct Answer: B
Solution :
As\[S=ut+\frac{1}{2}a{{t}^{2}}\]\[\therefore \]\[{{S}_{1}}=\frac{1}{2}a{{(10)}^{2}}=50a\] .....(i) \[As\ \ v=u+at\]\[\therefore \] velocity acquired by particle in 10 sec \[v=a\times 10\] For next 10 sec , \[{{S}_{2}}=(10a)\times 10+\frac{1}{2}\times {{(10)}^{2}}\] \[{{S}_{2}}=\]\[150a\] .....(ii) From (i) and (ii) \[{{S}_{1}}={{S}_{2}}/3\]
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