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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    A pendulum bob on a 2 m string is displaced 60o from the vertical and then released.  What is the speed of the bob as it passes through the lowest point in its path           [JIPMER 1999]

    A)             \[\sqrt{2}\,\,m/s\]

    B)                     \[\sqrt{9.8}\,\,m/s\]

    C)             4.43 m/s

    D)                      \[1/\sqrt{2}\,\,m/s\]

    Correct Answer: C

    Solution :

                    \[v=\sqrt{2gl(1-\cos \theta )}=\sqrt{2\times 9.8\times 2(1-\cos 60{}^\circ )}\]         \[=4.43\,m/s\]


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