A) Zero
B) \[6.675\times {{10}^{-5}}\,newton\]
C) \[6.675\times {{10}^{-11}}\,newton\]
D) \[6.675\times {{10}^{-8}}\,newton\]
Correct Answer: C
Solution :
\[F=G\frac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]\[=6.675\times \frac{1\times 1}{{{1}^{2}}}\times {{10}^{-11}}=6.675\times {{10}^{-11}}N\]
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