A) \[{{R}^{2}}\]
B) \[{{R}^{-2}}\]
C) \[{{R}^{4}}\]
D) \[{{R}^{-4}}\]
Correct Answer: C
Solution :
\[F=\frac{G\times m\times m}{{{(2R)}^{2}}}\]=\[\frac{G\times {{\left( \frac{4}{3}\pi {{R}^{3}}\rho \right)}^{2}}}{4{{R}^{2}}}\]\[=\frac{4}{9}{{\pi }^{2}}{{\rho }^{2}}{{R}^{4}}\] \ \[F\propto {{R}^{4}}\]
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