A) \[18\times {{10}^{25}}\]
B) Zero
C) \[27\times {{10}^{39}}\]
D) \[36\times {{10}^{21}}\]
Correct Answer: D
Solution :
\[m=6\times {{10}^{24}}kg,\] \[\omega =2\times {{10}^{-7}}rad/s,\]\[R=1.5\times {{10}^{11}}m\] The force exerted by the sun on the earth \[F=m{{\omega }^{2}}R\] By substituting the value we can get, \[F=36\times {{10}^{21}}N\]
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