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NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    Suppose the charge of a proton and an electron differ slightly. One of them is \[-\,e,\] the other is\[(e+\Delta e)\]. If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then \[\Delta e\] is of the order of [Given mass of hydrogen\[{{m}_{h}}=1.67\times {{10}^{-27}}kg\]] [NEET-2017]

    A) \[{{10}^{-47}}C\]

    B) \[{{10}^{-20}}C\]

    C) \[{{10}^{-23}}C\]

    D) \[{{10}^{-37}}C\]

    Correct Answer: D

    Solution :

    [d] \[{{F}_{e}}={{F}_{g}}\]
                            \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{\Delta {{e}^{2}}}{{{d}^{2}}}=\frac{G{{m}^{2}}}{{{d}^{2}}}\]
                \[9\times {{10}^{9}}(\Delta {{e}^{2}})=6.67\times {{10}^{-11}}\times 1.67\]\[\times {{10}^{-27}}\times 1.67\times {{10}^{-27}}\]
    \[\Delta {{e}^{2}}=\frac{6.67\times 1.67\times 1.67}{9}\times {{10}^{-74}}\]
    \[\Delta \Epsilon \approx {{10}^{-37}}\]


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