NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    A charge \[q\mu C\] is placed at the centre of a cube of a side 0.1 m, then the electric flux diverging from each face of the cube is:                    [AIPMT 2001]

    A) \[\frac{q\times {{10}^{-6}}}{24{{\varepsilon }_{0}}}\]

    B) \[\frac{q\times {{10}^{-4}}}{{{\varepsilon }_{0}}}\]

    C) \[\frac{q\times {{10}^{-6}}}{6{{\varepsilon }_{0}}}\]

    D) \[\frac{q\times {{10}^{-4}}}{12{{\varepsilon }_{0}}}\]

    Correct Answer: C

    Solution :

    [c] Key Idea: According to Gauss' law, total electric flux through a closed surface is equal to \[\frac{1}{{{\varepsilon }_{0}}}\]  rimes the total charge enclosed by the surface.
                From key idea, the electric flux emerging from the cube is
                            \[\phi =\frac{1}{{{\varepsilon }_{0}}}\times \text{charge}\,\,\text{enclosed}\]
                            \[=\frac{1}{{{\varepsilon }_{0}}}\times q\times {{10}^{-6}}\]
                Since, a cube has six faces, so electric flux through each face is,
                            \[\phi '=\frac{\phi }{6}=\frac{1}{6{{\varepsilon }_{0}}}\times q\times {{10}^{-6}}=\frac{q\times {{10}^{-6}}}{6{{\varepsilon }_{0}}}\]

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