A) \[4\sqrt{2}cm,\,\,\frac{\sqrt{2}}{225}cm\,\,{{s}^{-1}}\]
B) \[4\sqrt{2}cm,\,\,\frac{4}{225}cm\]
C) \[2\sqrt{4}cm,\,\,\frac{1}{225}cm\,\,{{s}^{-1}}\]
D) \[4\sqrt{2}cm,\,\,\frac{2}{225}cm\,\,{{s}^{-1}}\]
Correct Answer: A
Solution :
\[S=\sqrt{{{l}^{2}}+{{l}^{2}}}=\sqrt{2{{l}^{2}}}=l\sqrt{2}=4\sqrt{2}\] Average velocity\[=\frac{S}{t}\]\[=\frac{4\sqrt{2}}{15\times 60\,\,s}=\frac{\sqrt{2}}{225}cm\,\,{{s}^{-1}}\]
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