A) \[6.10\,\,m\,\,{{s}^{-2}}\]
B) \[8.10\,\,m\,\,{{s}^{-2}}\]
C) \[10.10\,\,m\,\,{{s}^{-2}}\]
D) \[12.10\,\,m\,\,{{s}^{-2}}\]
Correct Answer: B
Solution :
\[S=ut+\frac{1}{2}a{{t}^{2}}\] \[110=0\times 5.21+0.5\times a{{(5.21)}^{2}}\] \[=\frac{110}{13.57}=8.10\,\,m\,\,{{s}^{-2}}\]
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