A) Distance
B) Velocity
C) \[\frac{{{v}^{2}}-{{u}^{2}}}{2}\]
D) \[\frac{v-u}{t}\]
Correct Answer: C
Solution :
\[{{v}^{2}}-{{u}^{2}}=2aS\],\[\therefore \]\[a\times S=\frac{{{v}^{2}}-{{u}^{2}}}{2}\](\[a\times S\] is the area of the acceleration-displacement graph).
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