A) \[14\,\,kmph\]
B) \[5\,\,kmph\]
C) \[10\sqrt{2}kmph\]
D) \[10\,\,kmph\]
Correct Answer: C
Solution :
Let the velocities of the two ends of the train be \[u\] and \[v\] and the velocity of the middle point be\[{{v}_{1}}\]. \[\therefore \]The acceleration of the mid-point of the train\[=a=\frac{v_{1}^{2}-{{u}^{2}}}{2s}=\frac{{{v}^{2}}-v_{1}^{2}}{2s}\]\[\Rightarrow \] \[{{v}_{1}}=\sqrt{\frac{{{v}^{2}}+{{u}^{2}}}{2}}=\sqrt{\frac{{{6}^{2}}+{{8}^{2}}}{2}}\]
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