9th Class Science Time and Motion Question Bank Motion

  • question_answer
    A stone is dropped into a well in which the level of water is h below, the top of the well. If \[v\] is velocity of sound, then time T after which the splash is heard is equal to

    A)   \[\frac{2h}{v}\]                                              

    B)  \[\sqrt{\frac{2h}{v}}+\frac{h}{g}\]

    C)  \[\sqrt{\frac{2h}{g}}+\frac{h}{v}\]                            

    D)  \[\sqrt{\frac{h}{2g}}+\frac{2h}{v}\]

    Correct Answer: C

    Solution :

     Distance travelled by stone in water,\[h=\frac{1}{2}g{{t}^{2}}\] Time taken by stone to reach water,\[t=\sqrt{\frac{2h}{g}}\] Time taken by sound to reach the top of well,\[t'=\frac{h}{v}\] \[\therefore \]Total time\[=\sqrt{\frac{2h}{g}}+\frac{h}{v}\]


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