A) 18m
B) 6m
C) \[\frac{2}{3}m\]
D) \[\frac{2}{9}m\]
Correct Answer: A
Solution :
\[{{H}_{\max }}=\frac{{{u}^{2}}}{2g}\Rightarrow {{H}_{\max }}\propto \frac{1}{g}\] On planet B value of g is \[1/9\]times to that of A. So value of \[{{H}_{\max }}\]will become 9 times i.e. \[2\times 9=18\ metre\]
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