A) 1 : 1
B) 11 : 1
C) 1 : 2
D) 1 : 11
Correct Answer: B
Solution :
Time of ascent \[=\frac{u}{g}=6\ \sec \Rightarrow u=60\ m/s\] Distance in first second \[{{h}_{\text{first}}}=60-\frac{g}{2}(2\times 1-1)=55\ m\] Distance in seventh second will be equal to the distance in first second of vertical downward motion \[{{h}_{\text{seventh}}}=\frac{g}{2}(2\times 1-1)=5\ m\]Þ \[{{h}_{\text{first}}}/{{h}_{\text{seventh}}}\]\[=11:1\]
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