JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Motion Under Gravity

  • question_answer
    Time taken by an object falling from rest to cover the height of \[{{h}_{1}}\] and \[{{h}_{2}}\] is respectively \[{{t}_{1}}\] and \[{{t}_{2}}\] then the ratio of \[{{t}_{1}}\] to \[{{t}_{2}}\] is   [RPMT 1999; RPET 2002]

    A)             \[{{h}_{1}}\ :\ {{h}_{2}}\]  

    B)             \[\sqrt{{{h}_{1}}}\ :\ \sqrt{{{h}_{2}}}\]

    C)             \[{{h}_{1}}\ :\ 2{{h}_{2}}\]

    D)                      2h1 : h2

    Correct Answer: B

    Solution :

                    \[t=\sqrt{\frac{2h}{g}}\Rightarrow \frac{{{t}_{1}}}{{{t}_{2}}}=\sqrt{\frac{{{h}_{1}}}{{{h}_{2}}}}\]


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