JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Motion Under Gravity

  • question_answer
    With what velocity a ball be projected vertically so that the distance covered by it in 5th second is twice the distance it covers in its 6th second \[(g=10\,m/{{s}^{2}})\] [CPMT 1997; MH CET 2000]

    A)             58.8 m/s         

    B)             49 m/s

    C)             65 m/s

    D)                      19.6 m/s

    Correct Answer: C

    Solution :

                    \[{{h}_{{{n}^{th}}}}=u-\frac{g}{2}(2n-1)\]             \[{{h}_{{{5}^{th}}}}=u-\frac{10}{2}(2\times 5-1)=u-45\]             \[{{h}_{{{6}^{th}}}}=u-\frac{10}{2}(2\times 6-1)=u-55\]             Given \[{{h}_{{{5}^{th}}}}=2\times {{h}_{{{6}^{th}}}}\].By solving we get \[u=65\ m/s\]


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