A) 3 km/h
B) 4 km/h
C) 5 km/h
D) 12 km/h
Correct Answer: C
Solution :
For first case \[{{v}^{2}}-{{0}^{2}}=2gh\] Þ \[{{(3)}^{2}}=2gh\] For second case \[{{v}^{2}}={{(-u)}^{2}}+2gh\]\[={{4}^{2}}+{{3}^{2}}\]\[\therefore \]\[v=\]5km/h
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