A) 30 m
B) 10 m
C) 60 m
D) 20 m
Correct Answer: A
Solution :
If u is the initial velocity then distance covered by it in 2 sec \[S=ut+\frac{1}{2}a{{t}^{2}}=u\times 2+\frac{1}{2}\times 10\times 4=2u+20\] ?(i) Now distance covered by it in 3rd sec \[{{S}_{{{3}^{rd}}}}=u+\frac{g}{2}\left( 2\times 3-1 \right)10=u+25\] ?(ii) From(i) and (ii), \[2u+20=u+25\Rightarrow u=5\] \[\therefore \]\[S=2\times 5+20=30\ m\]
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