A) \[\sqrt{{{u}^{2}}+2gh}\]
B) \[\sqrt{2gh}\]
C) \[2gh\]
D) \[\sqrt{{{u}^{2}}-2gh}\]
Correct Answer: A
Solution :
Horizontal velocity of dropped packet \[=u\] Vertical velocity \[=\sqrt{2gh}\] \[\therefore \] Resultant velocity at earth \[=\sqrt{{{u}^{2}}+2gh}\]
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